Q2 value given: .09
P: 0.7
Q:0.3
P^2:0.49
Q^2:0.09
2PQ: 0.42
Population size: 1,000
1. Using Q^2, 0.09, you can find the Q value by taking the square root. The square root of 0.09 is 0.3
2. Subtracting 1.0 by . 3, you will get your P value, which will total to 0.7
3. Next, you will take the P value and square it- 0.7 squared is 0.49
4. Now Multiply 2PQ, or 2*0.3*0.7, which will total to 0.42
5. Last check that the Q^2, P^2, and 2PQ total to equal 1.0
6. Now that you have all your frequencies, you can find the number of individual for each genotype
by multiplying the frequency value of the genotypes by the population (1,000)
A) P^2- 0.49*1000= 490 Homozyqous dominant individuals
B) Q^2- 0.09*1000= 90 Homozygous recessive individuals
C) 2PQ- 0.42*1000= 420 Heterozygous individuals
From these calculations, we can note that 910 individuals or 0.91% display the dominant phenotype, 420 individuals are carriers, and only 9% of individuals express the recessive phenotype.
